Johnston’s 73 leaves him tied for 18th at Patriot All-America tournament

OC sophomore Sam Johnston is tied for 18th after two rounds of the Patriot All-America Invitational.
OC sophomore Sam Johnston is tied for 18th after two rounds of the Patriot All-America Invitational.

LITCHFIELD PARK, Ariz. (Dec. 30, 2013) – Oklahoma Christian’s Sam Johnston fired a 3-over-par 73 on Monday in the second round of the Patriot All-America Invitational and remains in the hunt for a top-10 finish.

Johnston, at 4-over 144 after two rounds on the Gold Course at The Wigwam, is among a group of six golfers tied for 18th in the 84-man field. The sophomore from San Diego is just three shots out of 10th place entering the final round on Tuesday.

The tournament is an all-star event that features All-Americans from the previous season in NCAA Divisions I, II and III, as well as All-Americans from the NAIA, NJCAA and American Junior Golf Association ranks. Last spring, Johnston became OC’s first Division II All-American in any sport, earning second-team honors.

Birdies on No. 2 and No. 4 put Johnston at 1-under for the tournament, but he recorded consecutive bogeys on No. 5 and No. 6. He got back to even par with a birdie on the par-3 No. 11 and was back at 1-under after a birdie at No. 13 before disaster struck.

Johnson bogeyed No. 14, then recorded a triple bogey on No. 15 and another bogey on No. 18 to finish the round at 4-over.

Kyle Westmoreland of Air Force leads the tournament at 4-under, one shot ahead of Thomas Lim of Oregon.

The tournament benefits Folds of Honor, a charitable organization that provides college scholarships for children and spouses of U.S. military service members who are killed or disabled while serving in the nation’s armed forces.